4351231335053 has 4 divisors (see below), whose sum is σ = 4355371423008. Its totient is φ = 4347091247100.

The previous prime is 4351231334959. The next prime is 4351231335083. The reversal of 4351231335053 is 3505331321534.

4351231335053 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4351231335053 - 2¹⁰ = 4351231334029 is a prime.

It is a super-2 number, since 2×4351231335053² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4351231334998 and 4351231335016.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4351231335083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2070042401 + ... + 2070044502.

It is an arithmetic number, because the mean of its divisors is an integer number (1088842855752).

Almost surely, 2^{4351231335053} is an apocalyptic number.

It is an amenable number.

4351231335053 is a deficient number, since it is larger than the sum of its proper divisors (4140087955).

4351231335053 is a wasteful number, since it uses less digits than its factorization.

4351231335053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4140087954.

The product of its (nonzero) digits is 243000, while the sum is 38.

Adding to 4351231335053 its reverse (3505331321534), we get a palindrome (7856562656587).

The spelling of 4351231335053 in words is "four trillion, three hundred fifty-one billion, two hundred thirty-one million, three hundred thirty-five thousand, fifty-three".