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4352022113 is a prime number
BaseRepresentation
bin1000000110110011…
…01001011001100001
3102020022002122000012
410003121221121201
532403104201423
61555502534305
7212563402055
oct40331513141
912208078005
104352022113
11193366a69a
12a15597395
1354483511a
142d3dc9c65
151a710d078
hex103669661

4352022113 has 2 divisors, whose sum is σ = 4352022114. Its totient is φ = 4352022112.

The previous prime is 4352022097. The next prime is 4352022127. The reversal of 4352022113 is 3112202534.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3270467344 + 1081554769 = 57188^2 + 32887^2 .

It is a cyclic number.

It is not a de Polignac number, because 4352022113 - 24 = 4352022097 is a prime.

It is not a weakly prime, because it can be changed into another prime (4352022163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2176011056 + 2176011057.

It is an arithmetic number, because the mean of its divisors is an integer number (2176011057).

Almost surely, 24352022113 is an apocalyptic number.

It is an amenable number.

4352022113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4352022113 is an equidigital number, since it uses as much as digits as its factorization.

4352022113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 4352022113 is about 65969.8576093658. The cubic root of 4352022113 is about 1632.6648060086.

Adding to 4352022113 its reverse (3112202534), we get a palindrome (7464224647).

The spelling of 4352022113 in words is "four billion, three hundred fifty-two million, twenty-two thousand, one hundred thirteen".