Base | Representation |
---|---|
bin | 111111010101001110001… |
… | …010010101000000010011 |
3 | 120102001120020210122100011 |
4 | 333111032022111000103 |
5 | 1032301111434414141 |
6 | 13131155545535351 |
7 | 626300264556541 |
oct | 77251612250023 |
9 | 16361506718304 |
10 | 4352113201171 |
11 | 14287a249626a |
12 | 5a3575aa4557 |
13 | 257530427848 |
14 | 1109016d6d91 |
15 | 7831d7d2881 |
hex | 3f54e295013 |
4352113201171 has 2 divisors, whose sum is σ = 4352113201172. Its totient is φ = 4352113201170.
The previous prime is 4352113201153. The next prime is 4352113201291. The reversal of 4352113201171 is 1711023112534.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4352113201171 - 237 = 4214674247699 is a prime.
It is not a weakly prime, because it can be changed into another prime (4352113201771) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2176056600585 + 2176056600586.
It is an arithmetic number, because the mean of its divisors is an integer number (2176056600586).
Almost surely, 24352113201171 is an apocalyptic number.
4352113201171 is a deficient number, since it is larger than the sum of its proper divisors (1).
4352113201171 is an equidigital number, since it uses as much as digits as its factorization.
4352113201171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 31.
The spelling of 4352113201171 in words is "four trillion, three hundred fifty-two billion, one hundred thirteen million, two hundred one thousand, one hundred seventy-one".
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