Base | Representation |
---|---|
bin | 111111010110001011101… |
… | …000000101110101111001 |
3 | 120102011020010012122210122 |
4 | 333112023220011311321 |
5 | 1032310214432213221 |
6 | 13131450144223025 |
7 | 626334655665626 |
oct | 77261350056571 |
9 | 16364203178718 |
10 | 4353144413561 |
11 | 1429181598409 |
12 | 5a380330aa75 |
13 | 257665c727a8 |
14 | 11099c64b34d |
15 | 7837e0cbeab |
hex | 3f58ba05d79 |
4353144413561 has 2 divisors, whose sum is σ = 4353144413562. Its totient is φ = 4353144413560.
The previous prime is 4353144413461. The next prime is 4353144413609. The reversal of 4353144413561 is 1653144413534.
4353144413561 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2928356027536 + 1424788386025 = 1711244^2 + 1193645^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4353144413561 is a prime.
It is not a weakly prime, because it can be changed into another prime (4353144413461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2176572206780 + 2176572206781.
It is an arithmetic number, because the mean of its divisors is an integer number (2176572206781).
Almost surely, 24353144413561 is an apocalyptic number.
It is an amenable number.
4353144413561 is a deficient number, since it is larger than the sum of its proper divisors (1).
4353144413561 is an equidigital number, since it uses as much as digits as its factorization.
4353144413561 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1036800, while the sum is 44.
The spelling of 4353144413561 in words is "four trillion, three hundred fifty-three billion, one hundred forty-four million, four hundred thirteen thousand, five hundred sixty-one".
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