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4371245113 is a prime number
BaseRepresentation
bin1000001001000101…
…11110100000111001
3102021122021021000011
410010202332200321
532423014320423
62001430541521
7213215653564
oct40442764071
912248237004
104371245113
1119434aa174
12a1bb078a1
13548805991
142d67914db
151a8b58b0d
hex1048be839

4371245113 has 2 divisors, whose sum is σ = 4371245114. Its totient is φ = 4371245112.

The previous prime is 4371245107. The next prime is 4371245147. The reversal of 4371245113 is 3115421734.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3506179369 + 865065744 = 59213^2 + 29412^2 .

It is a cyclic number.

It is not a de Polignac number, because 4371245113 - 29 = 4371244601 is a prime.

It is not a weakly prime, because it can be changed into another prime (4371240113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2185622556 + 2185622557.

It is an arithmetic number, because the mean of its divisors is an integer number (2185622557).

Almost surely, 24371245113 is an apocalyptic number.

It is an amenable number.

4371245113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4371245113 is an equidigital number, since it uses as much as digits as its factorization.

4371245113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10080, while the sum is 31.

The square root of 4371245113 is about 66115.3924060048. The cubic root of 4371245113 is about 1635.0651170030.

Adding to 4371245113 its reverse (3115421734), we get a palindrome (7486666847).

The spelling of 4371245113 in words is "four billion, three hundred seventy-one million, two hundred forty-five thousand, one hundred thirteen".