Base | Representation |
---|---|
bin | 1000001001000101… |
… | …11110100000111001 |
3 | 102021122021021000011 |
4 | 10010202332200321 |
5 | 32423014320423 |
6 | 2001430541521 |
7 | 213215653564 |
oct | 40442764071 |
9 | 12248237004 |
10 | 4371245113 |
11 | 19434aa174 |
12 | a1bb078a1 |
13 | 548805991 |
14 | 2d67914db |
15 | 1a8b58b0d |
hex | 1048be839 |
4371245113 has 2 divisors, whose sum is σ = 4371245114. Its totient is φ = 4371245112.
The previous prime is 4371245107. The next prime is 4371245147. The reversal of 4371245113 is 3115421734.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3506179369 + 865065744 = 59213^2 + 29412^2 .
It is a cyclic number.
It is not a de Polignac number, because 4371245113 - 29 = 4371244601 is a prime.
It is not a weakly prime, because it can be changed into another prime (4371240113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2185622556 + 2185622557.
It is an arithmetic number, because the mean of its divisors is an integer number (2185622557).
Almost surely, 24371245113 is an apocalyptic number.
It is an amenable number.
4371245113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4371245113 is an equidigital number, since it uses as much as digits as its factorization.
4371245113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10080, while the sum is 31.
The square root of 4371245113 is about 66115.3924060048. The cubic root of 4371245113 is about 1635.0651170030.
Adding to 4371245113 its reverse (3115421734), we get a palindrome (7486666847).
The spelling of 4371245113 in words is "four billion, three hundred seventy-one million, two hundred forty-five thousand, one hundred thirteen".
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