Base | Representation |
---|---|
bin | 1100110001111100111… |
… | …10010101101101000111 |
3 | 1112222111001121102210220 |
4 | 12120332132111231013 |
5 | 24143322002223212 |
6 | 533422530515423 |
7 | 43504112152566 |
oct | 6307636255507 |
9 | 1488431542726 |
10 | 439134804807 |
11 | 15a266170496 |
12 | 71135435b73 |
13 | 3254439218a |
14 | 1737b8b3bdd |
15 | b65247b38c |
hex | 663e795b47 |
439134804807 has 4 divisors (see below), whose sum is σ = 585513073080. Its totient is φ = 292756536536.
The previous prime is 439134804781. The next prime is 439134804809. The reversal of 439134804807 is 708408431934.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 439134804807 - 215 = 439134772039 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 439134804807.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (439134804809) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73189134132 + ... + 73189134137.
It is an arithmetic number, because the mean of its divisors is an integer number (146378268270).
Almost surely, 2439134804807 is an apocalyptic number.
439134804807 is a deficient number, since it is larger than the sum of its proper divisors (146378268273).
439134804807 is a wasteful number, since it uses less digits than its factorization.
439134804807 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 146378268272.
The product of its (nonzero) digits is 2322432, while the sum is 51.
The spelling of 439134804807 in words is "four hundred thirty-nine billion, one hundred thirty-four million, eight hundred four thousand, eight hundred seven".
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