Search a number
-
+
439134804809 is a prime number
BaseRepresentation
bin1100110001111100111…
…10010101101101001001
31112222111001121102210222
412120332132111231021
524143322002223214
6533422530515425
743504112152601
oct6307636255511
91488431542728
10439134804809
1115a266170498
1271135435b75
133254439218c
141737b8b3c01
15b65247b38e
hex663e795b49

439134804809 has 2 divisors, whose sum is σ = 439134804810. Its totient is φ = 439134804808.

The previous prime is 439134804781. The next prime is 439134804811. The reversal of 439134804809 is 908408431934.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 439108998409 + 25806400 = 662653^2 + 5080^2 .

It is a cyclic number.

It is not a de Polignac number, because 439134804809 - 28 = 439134804553 is a prime.

It is a Sophie Germain prime.

Together with 439134804811, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (439134804839) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 219567402404 + 219567402405.

It is an arithmetic number, because the mean of its divisors is an integer number (219567402405).

Almost surely, 2439134804809 is an apocalyptic number.

It is an amenable number.

439134804809 is a deficient number, since it is larger than the sum of its proper divisors (1).

439134804809 is an equidigital number, since it uses as much as digits as its factorization.

439134804809 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2985984, while the sum is 53.

The spelling of 439134804809 in words is "four hundred thirty-nine billion, one hundred thirty-four million, eight hundred four thousand, eight hundred nine".