Base | Representation |
---|---|
bin | 10100000000111001000101… |
… | …10001100110011111000011 |
3 | 12202211102101011021100210011 |
4 | 22000130202301212133003 |
5 | 21232034230001411042 |
6 | 233334232031045351 |
7 | 12161461262452024 |
oct | 1200344261463703 |
9 | 182742334240704 |
10 | 44011113310147 |
11 | 13029010107085 |
12 | 4b29794970857 |
13 | 1b732cb911759 |
14 | ac2213782c4b |
15 | 514c6b699a17 |
hex | 280722c667c3 |
44011113310147 has 2 divisors, whose sum is σ = 44011113310148. Its totient is φ = 44011113310146.
The previous prime is 44011113310133. The next prime is 44011113310201. The reversal of 44011113310147 is 74101331111044.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-44011113310147 is a prime.
It is not a weakly prime, because it can be changed into another prime (44011113380147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22005556655073 + 22005556655074.
It is an arithmetic number, because the mean of its divisors is an integer number (22005556655074).
Almost surely, 244011113310147 is an apocalyptic number.
44011113310147 is a deficient number, since it is larger than the sum of its proper divisors (1).
44011113310147 is an equidigital number, since it uses as much as digits as its factorization.
44011113310147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 31.
The spelling of 44011113310147 in words is "forty-four trillion, eleven billion, one hundred thirteen million, three hundred ten thousand, one hundred forty-seven".
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