Base | Representation |
---|---|
bin | 101000111111010100… |
… | …101011100001101011 |
3 | 11012121021110020102022 |
4 | 220333110223201223 |
5 | 1210114041334411 |
6 | 32115135055055 |
7 | 3115442220014 |
oct | 507724534153 |
9 | 135537406368 |
10 | 44012058731 |
11 | 17735729163 |
12 | 864367148b |
13 | 41c5336904 |
14 | 21b738000b |
15 | 1228d3eedb |
hex | a3f52b86b |
44012058731 has 2 divisors, whose sum is σ = 44012058732. Its totient is φ = 44012058730.
The previous prime is 44012058697. The next prime is 44012058781. The reversal of 44012058731 is 13785021044.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-44012058731 is a prime.
It is a super-2 number, since 2×440120587312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 44012058691 and 44012058700.
It is not a weakly prime, because it can be changed into another prime (44012058781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22006029365 + 22006029366.
It is an arithmetic number, because the mean of its divisors is an integer number (22006029366).
Almost surely, 244012058731 is an apocalyptic number.
44012058731 is a deficient number, since it is larger than the sum of its proper divisors (1).
44012058731 is an equidigital number, since it uses as much as digits as its factorization.
44012058731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 35.
Adding to 44012058731 its reverse (13785021044), we get a palindrome (57797079775).
The spelling of 44012058731 in words is "forty-four billion, twelve million, fifty-eight thousand, seven hundred thirty-one".
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