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440132525399993 is a prime number
BaseRepresentation
bin110010000010011000101011…
…0110101001001111110111001
32010201101020222110002222121012
41210010301112311021332321
5430142112403000244433
64200030031342323305
7161464345165221536
oct14404612665117671
92121336873088535
10440132525399993
111182701793a2228
1241444770289535
1315b7841bc7075a
147a98756771d8d
1535d3ccc755848
hex1904c56d49fb9

440132525399993 has 2 divisors, whose sum is σ = 440132525399994. Its totient is φ = 440132525399992.

The previous prime is 440132525399971. The next prime is 440132525400077. The reversal of 440132525399993 is 399993525231044.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 398147270362384 + 41985255037609 = 19953628^2 + 6479603^2 .

It is a cyclic number.

It is not a de Polignac number, because 440132525399993 - 232 = 440128230432697 is a prime.

It is a super-3 number, since 3×4401325253999933 (a number of 45 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (440132525339993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220066262699996 + 220066262699997.

It is an arithmetic number, because the mean of its divisors is an integer number (220066262699997).

Almost surely, 2440132525399993 is an apocalyptic number.

It is an amenable number.

440132525399993 is a deficient number, since it is larger than the sum of its proper divisors (1).

440132525399993 is an equidigital number, since it uses as much as digits as its factorization.

440132525399993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 283435200, while the sum is 68.

The spelling of 440132525399993 in words is "four hundred forty trillion, one hundred thirty-two billion, five hundred twenty-five million, three hundred ninety-nine thousand, nine hundred ninety-three".