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44023150043113 is a prime number
BaseRepresentation
bin10100000001001111100000…
…01110000101111111101001
312202212120110000111202021211
422000213300032011333221
521232233402402334423
6233343542252033121
712162365461135663
oct1200476016057751
9182776400452254
1044023150043113
111303312757777a
124b2bb93a627a1
131b74499567a57
14ac2a36203533
1551522327410d
hex2809f0385fe9

44023150043113 has 2 divisors, whose sum is σ = 44023150043114. Its totient is φ = 44023150043112.

The previous prime is 44023150043099. The next prime is 44023150043129. The reversal of 44023150043113 is 31134005132044.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31099326362329 + 12923823680784 = 5576677^2 + 3594972^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-44023150043113 is a prime.

It is a super-3 number, since 3×440231500431133 (a number of 42 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (44023150043153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22011575021556 + 22011575021557.

It is an arithmetic number, because the mean of its divisors is an integer number (22011575021557).

Almost surely, 244023150043113 is an apocalyptic number.

It is an amenable number.

44023150043113 is a deficient number, since it is larger than the sum of its proper divisors (1).

44023150043113 is an equidigital number, since it uses as much as digits as its factorization.

44023150043113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 44023150043113 its reverse (31134005132044), we get a palindrome (75157155175157).

The spelling of 44023150043113 in words is "forty-four trillion, twenty-three billion, one hundred fifty million, forty-three thousand, one hundred thirteen".