Base | Representation |
---|---|
bin | 100000000010100000110… |
… | …1011001100100100001111 |
3 | 120120222001112110220111012 |
4 | 1000011001223030210033 |
5 | 1034121222442233403 |
6 | 13210525224315435 |
7 | 633065300441141 |
oct | 100050153144417 |
9 | 16528045426435 |
10 | 4403443321103 |
11 | 1448542a59092 |
12 | 5b1500312b7b |
13 | 25c320919c88 |
14 | 1131b0948c91 |
15 | 79824d16ed8 |
hex | 40141acc90f |
4403443321103 has 4 divisors (see below), whose sum is σ = 4403451523968. Its totient is φ = 4403435118240.
The previous prime is 4403443321093. The next prime is 4403443321153. The reversal of 4403443321103 is 3011233443044.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4403443321103 - 214 = 4403443304719 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 4403443321103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4403443321153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3235226 + ... + 4390167.
It is an arithmetic number, because the mean of its divisors is an integer number (1100862880992).
Almost surely, 24403443321103 is an apocalyptic number.
4403443321103 is a deficient number, since it is larger than the sum of its proper divisors (8202865).
4403443321103 is an equidigital number, since it uses as much as digits as its factorization.
4403443321103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8202864.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 4403443321103 its reverse (3011233443044), we get a palindrome (7414676764147).
The spelling of 4403443321103 in words is "four trillion, four hundred three billion, four hundred forty-three million, three hundred twenty-one thousand, one hundred three".
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