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4405130042017 is a prime number
BaseRepresentation
bin100000000011010011000…
…1101100001101010100001
3120121010102002100012121011
41000012212031201222201
51034133201242321032
613211404440500521
7633155141355625
oct100064615415241
916533362305534
104405130042017
111449229081511
125b18b117a741
1325c52c1c72a3
141132d0975185
15798c2e46247
hex401a6361aa1

4405130042017 has 2 divisors, whose sum is σ = 4405130042018. Its totient is φ = 4405130042016.

The previous prime is 4405130041913. The next prime is 4405130042119. The reversal of 4405130042017 is 7102400315044.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2536553134336 + 1868576907681 = 1592656^2 + 1366959^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4405130042017 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4405130042017.

It is not a weakly prime, because it can be changed into another prime (4405130442017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2202565021008 + 2202565021009.

It is an arithmetic number, because the mean of its divisors is an integer number (2202565021009).

Almost surely, 24405130042017 is an apocalyptic number.

It is an amenable number.

4405130042017 is a deficient number, since it is larger than the sum of its proper divisors (1).

4405130042017 is an equidigital number, since it uses as much as digits as its factorization.

4405130042017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13440, while the sum is 31.

The spelling of 4405130042017 in words is "four trillion, four hundred five billion, one hundred thirty million, forty-two thousand, seventeen".