Base | Representation |
---|---|
bin | 100000000011010101010… |
… | …0100011010110100011001 |
3 | 120121010121011220120211222 |
4 | 1000012222210122310121 |
5 | 1034133324001332103 |
6 | 13211420011501425 |
7 | 633160016654666 |
oct | 100065244326431 |
9 | 16533534816758 |
10 | 4405203152153 |
11 | 1449266377211 |
12 | 5b1911757875 |
13 | 25c5413b461b |
14 | 1132da566a6d |
15 | 798c9588638 |
hex | 401aa91ad19 |
4405203152153 has 2 divisors, whose sum is σ = 4405203152154. Its totient is φ = 4405203152152.
The previous prime is 4405203152131. The next prime is 4405203152183. The reversal of 4405203152153 is 3512513025044.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3012123389209 + 1393079762944 = 1735547^2 + 1180288^2 .
It is a cyclic number.
It is not a de Polignac number, because 4405203152153 - 224 = 4405186374937 is a prime.
It is not a weakly prime, because it can be changed into another prime (4405203152183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2202601576076 + 2202601576077.
It is an arithmetic number, because the mean of its divisors is an integer number (2202601576077).
Almost surely, 24405203152153 is an apocalyptic number.
It is an amenable number.
4405203152153 is a deficient number, since it is larger than the sum of its proper divisors (1).
4405203152153 is an equidigital number, since it uses as much as digits as its factorization.
4405203152153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 4405203152153 its reverse (3512513025044), we get a palindrome (7917716177197).
The spelling of 4405203152153 in words is "four trillion, four hundred five billion, two hundred three million, one hundred fifty-two thousand, one hundred fifty-three".
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