Base | Representation |
---|---|
bin | 100000000110110100111… |
… | …0110001110100110010001 |
3 | 120121211222011011120000021 |
4 | 1000031221312032212101 |
5 | 1034244211023024431 |
6 | 13215100354223441 |
7 | 633543666431113 |
oct | 100155166164621 |
9 | 16554864146007 |
10 | 4412707236241 |
11 | 14514672176a7 |
12 | 5b3266884b81 |
13 | 260168c72575 |
14 | 11380d01d3b3 |
15 | 79bb8275b11 |
hex | 40369d8e991 |
4412707236241 has 2 divisors, whose sum is σ = 4412707236242. Its totient is φ = 4412707236240.
The previous prime is 4412707236193. The next prime is 4412707236281. The reversal of 4412707236241 is 1426327072144.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3783009440016 + 629697796225 = 1944996^2 + 793535^2 .
It is a cyclic number.
It is not a de Polignac number, because 4412707236241 - 213 = 4412707228049 is a prime.
It is not a weakly prime, because it can be changed into another prime (4412707236281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2206353618120 + 2206353618121.
It is an arithmetic number, because the mean of its divisors is an integer number (2206353618121).
Almost surely, 24412707236241 is an apocalyptic number.
It is an amenable number.
4412707236241 is a deficient number, since it is larger than the sum of its proper divisors (1).
4412707236241 is an equidigital number, since it uses as much as digits as its factorization.
4412707236241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 451584, while the sum is 43.
The spelling of 4412707236241 in words is "four trillion, four hundred twelve billion, seven hundred seven million, two hundred thirty-six thousand, two hundred forty-one".
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