44130000041 has 2 divisors, whose sum is σ = 44130000042. Its totient is φ = 44130000040.

The previous prime is 44129999989. The next prime is 44130000067. The reversal of 44130000041 is 14000003144.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33892810000 + 10237190041 = 184100^2 + 101179^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-44130000041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 44129999974 and 44130000019.

It is not a weakly prime, because it can be changed into another prime (44130000841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22065000020 + 22065000021.

It is an arithmetic number, because the mean of its divisors is an integer number (22065000021).

Almost surely, 2^44130000041 is an apocalyptic number.

It is an amenable number.

44130000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

44130000041 is an equidigital number, since it uses as much as digits as its factorization.

44130000041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 44130000041 its reverse (14000003144), we get a palindrome (58130003185).

The spelling of 44130000041 in words is "forty-four billion, one hundred thirty million, forty-one", and thus it is an aban number.