Base | Representation |
---|---|
bin | 1100110101111111000… |
… | …01111111111100011001 |
3 | 1120012001221212000200120 |
4 | 12122333201333330121 |
5 | 24212240301300423 |
6 | 534421435023453 |
7 | 43611553215333 |
oct | 6327741777431 |
9 | 1505057760616 |
10 | 441300025113 |
11 | 1601773a5562 |
12 | 7163a59ab89 |
13 | 327cab3711c |
14 | 1750529a453 |
15 | b72c5c7ee3 |
hex | 66bf87ff19 |
441300025113 has 8 divisors (see below), whose sum is σ = 597182123808. Its totient is φ = 289808971584.
The previous prime is 441300025091. The next prime is 441300025129. The reversal of 441300025113 is 311520003144.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 441300025113 - 217 = 441299894041 is a prime.
It is a super-3 number, since 3×4413000251133 (a number of 36 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (441300025183) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1097761056 + ... + 1097761457.
It is an arithmetic number, because the mean of its divisors is an integer number (74647765476).
Almost surely, 2441300025113 is an apocalyptic number.
It is an amenable number.
441300025113 is a deficient number, since it is larger than the sum of its proper divisors (155882098695).
441300025113 is a wasteful number, since it uses less digits than its factorization.
441300025113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2195522583.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 441300025113 its reverse (311520003144), we get a palindrome (752820028257).
The spelling of 441300025113 in words is "four hundred forty-one billion, three hundred million, twenty-five thousand, one hundred thirteen".
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