Base | Representation |
---|---|
bin | 1100110110000011111… |
… | …00000110000101010001 |
3 | 1120012011202212022122112 |
4 | 12123001330012011101 |
5 | 24212331121423213 |
6 | 534425440515105 |
7 | 43612553451053 |
oct | 6330174060521 |
9 | 1505152768575 |
10 | 441340420433 |
11 | 160198186120 |
12 | 7165001ba95 |
13 | 3280630b893 |
14 | 1750a7b38d3 |
15 | b730e06ea8 |
hex | 66c1f06151 |
441340420433 has 32 divisors (see below), whose sum is σ = 490515277824. Its totient is φ = 393751800000.
The previous prime is 441340420403. The next prime is 441340420513. The reversal of 441340420433 is 334024043144.
It is a cyclic number.
It is not a de Polignac number, because 441340420433 - 26 = 441340420369 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 441340420433.
It is not an unprimeable number, because it can be changed into a prime (441340420403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 207103778 + ... + 207105908.
It is an arithmetic number, because the mean of its divisors is an integer number (15328602432).
Almost surely, 2441340420433 is an apocalyptic number.
It is an amenable number.
441340420433 is a deficient number, since it is larger than the sum of its proper divisors (49174857391).
441340420433 is a wasteful number, since it uses less digits than its factorization.
441340420433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3797.
The product of its (nonzero) digits is 55296, while the sum is 32.
Adding to 441340420433 its reverse (334024043144), we get a palindrome (775364463577).
The spelling of 441340420433 in words is "four hundred forty-one billion, three hundred forty million, four hundred twenty thousand, four hundred thirty-three".
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