Base | Representation |
---|---|
bin | 10100000100100101100000… |
… | …00001000110100001000011 |
3 | 12210021112222200121111102211 |
4 | 22002102300001012201003 |
5 | 21241124144433400142 |
6 | 233512422334322551 |
7 | 12203603463230512 |
oct | 1202226001064103 |
9 | 183245880544384 |
10 | 44138037012547 |
11 | 130779222432a5 |
12 | 4b4a2b7359457 |
13 | 1b8227836993a |
14 | ac8414464679 |
15 | 5181e93e7917 |
hex | 2824b0046843 |
44138037012547 has 2 divisors, whose sum is σ = 44138037012548. Its totient is φ = 44138037012546.
The previous prime is 44138037012539. The next prime is 44138037012581. The reversal of 44138037012547 is 74521073083144.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 44138037012547 - 23 = 44138037012539 is a prime.
It is a super-2 number, since 2×441380370125472 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 44138037012547.
It is not a weakly prime, because it can be changed into another prime (44138037012347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22069018506273 + 22069018506274.
It is an arithmetic number, because the mean of its divisors is an integer number (22069018506274).
Almost surely, 244138037012547 is an apocalyptic number.
44138037012547 is a deficient number, since it is larger than the sum of its proper divisors (1).
44138037012547 is an equidigital number, since it uses as much as digits as its factorization.
44138037012547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2257920, while the sum is 49.
The spelling of 44138037012547 in words is "forty-four trillion, one hundred thirty-eight billion, thirty-seven million, twelve thousand, five hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •