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441749107244153 is a prime number
BaseRepresentation
bin110010001110001001011101…
…0100111011111110001111001
32010221002210122211001102111202
41210130102322213133301321
5430400104132423303103
64203304423245503545
7162022214454166562
oct14434227247376171
92127083584042452
10441749107244153
11118833820733655
1241665b2a271bb5
1315c649ba35c6a7
147b12ab13ad169
153610d94963988
hex191c4ba9dfc79

441749107244153 has 2 divisors, whose sum is σ = 441749107244154. Its totient is φ = 441749107244152.

The previous prime is 441749107244117. The next prime is 441749107244219. The reversal of 441749107244153 is 351442701947144.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 432295745308729 + 9453361935424 = 20791723^2 + 3074632^2 .

It is a cyclic number.

It is not a de Polignac number, because 441749107244153 - 212 = 441749107240057 is a prime.

It is not a weakly prime, because it can be changed into another prime (441749107243153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220874553622076 + 220874553622077.

It is an arithmetic number, because the mean of its divisors is an integer number (220874553622077).

Almost surely, 2441749107244153 is an apocalyptic number.

It is an amenable number.

441749107244153 is a deficient number, since it is larger than the sum of its proper divisors (1).

441749107244153 is an equidigital number, since it uses as much as digits as its factorization.

441749107244153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13547520, while the sum is 56.

The spelling of 441749107244153 in words is "four hundred forty-one trillion, seven hundred forty-nine billion, one hundred seven million, two hundred forty-four thousand, one hundred fifty-three".