Base | Representation |
---|---|
bin | 1100110111100010011… |
… | …11110000110100111011 |
3 | 1120021020002022200202011 |
4 | 12123301033300310323 |
5 | 24220442312333103 |
6 | 535040312150351 |
7 | 43641331613314 |
oct | 6336117606473 |
9 | 1507202280664 |
10 | 442134105403 |
11 | 1605651a3411 |
12 | 718319983b7 |
13 | 32901890263 |
14 | 17583d7760b |
15 | b77a932d6d |
hex | 66f13f0d3b |
442134105403 has 2 divisors, whose sum is σ = 442134105404. Its totient is φ = 442134105402.
The previous prime is 442134105353. The next prime is 442134105409. The reversal of 442134105403 is 304501431244.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-442134105403 is a prime.
It is a super-2 number, since 2×4421341054032 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (442134105409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221067052701 + 221067052702.
It is an arithmetic number, because the mean of its divisors is an integer number (221067052702).
Almost surely, 2442134105403 is an apocalyptic number.
442134105403 is a deficient number, since it is larger than the sum of its proper divisors (1).
442134105403 is an equidigital number, since it uses as much as digits as its factorization.
442134105403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 442134105403 its reverse (304501431244), we get a palindrome (746635536647).
The spelling of 442134105403 in words is "four hundred forty-two billion, one hundred thirty-four million, one hundred five thousand, four hundred three".
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