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442400140224121 is a prime number
BaseRepresentation
bin110010010010111000100111…
…1001101001110011001111001
32011000102001002102110110202011
41210211301033031032121321
5430441240441344132441
64204523452502005521
7162120232614211012
oct14445611715163171
92130361072413664
10442400140224121
11118a64933899352
124175013ba168a1
1315cb1200a73261
147b363d1238009
153622c99bbe581
hex1925c4f34e679

442400140224121 has 2 divisors, whose sum is σ = 442400140224122. Its totient is φ = 442400140224120.

The previous prime is 442400140224079. The next prime is 442400140224157. The reversal of 442400140224121 is 121422041004244.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 307048695068025 + 135351445156096 = 17522805^2 + 11634064^2 .

It is a cyclic number.

It is not a de Polignac number, because 442400140224121 - 215 = 442400140191353 is a prime.

It is a super-2 number, since 2×4424001402241212 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (442400140224521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221200070112060 + 221200070112061.

It is an arithmetic number, because the mean of its divisors is an integer number (221200070112061).

Almost surely, 2442400140224121 is an apocalyptic number.

It is an amenable number.

442400140224121 is a deficient number, since it is larger than the sum of its proper divisors (1).

442400140224121 is an equidigital number, since it uses as much as digits as its factorization.

442400140224121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16384, while the sum is 31.

Adding to 442400140224121 its reverse (121422041004244), we get a palindrome (563822181228365).

The spelling of 442400140224121 in words is "four hundred forty-two trillion, four hundred billion, one hundred forty million, two hundred twenty-four thousand, one hundred twenty-one".