Base | Representation |
---|---|
bin | 100000001100001001011… |
… | …0000100101100000110011 |
3 | 120122221110022001222112111 |
4 | 1000120102300211200303 |
5 | 1034441110021310311 |
6 | 13224230122110151 |
7 | 634430043243241 |
oct | 100302260454063 |
9 | 16587408058474 |
10 | 4424131041331 |
11 | 14562996aa531 |
12 | 5b551464b357 |
13 | 261269924851 |
14 | 1141b42cd791 |
15 | 7a13612bd21 |
hex | 40612c25833 |
4424131041331 has 2 divisors, whose sum is σ = 4424131041332. Its totient is φ = 4424131041330.
The previous prime is 4424131041311. The next prime is 4424131041367. The reversal of 4424131041331 is 1331401314244.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4424131041331 - 217 = 4424130910259 is a prime.
It is a super-2 number, since 2×44241310413312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4424131041293 and 4424131041302.
It is not a weakly prime, because it can be changed into another prime (4424131041301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2212065520665 + 2212065520666.
It is an arithmetic number, because the mean of its divisors is an integer number (2212065520666).
Almost surely, 24424131041331 is an apocalyptic number.
4424131041331 is a deficient number, since it is larger than the sum of its proper divisors (1).
4424131041331 is an equidigital number, since it uses as much as digits as its factorization.
4424131041331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 4424131041331 its reverse (1331401314244), we get a palindrome (5755532355575).
The spelling of 4424131041331 in words is "four trillion, four hundred twenty-four billion, one hundred thirty-one million, forty-one thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •