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4424132443151 = 42110508628131
BaseRepresentation
bin100000001100001001011…
…0101111011110000001111
3120122221110101201012110202
41000120102311323300033
51034441110401140101
613224230212124115
7634430061202211
oct100302265736017
916587411635422
104424132443151
11145629a477763
125b551500663b
13261269cc5925
141141b45765b1
157a13630736b
hex40612d7bc0f

4424132443151 has 4 divisors (see below), whose sum is σ = 4434641071704. Its totient is φ = 4413623814600.

The previous prime is 4424132443099. The next prime is 4424132443177. The reversal of 4424132443151 is 1513442314244.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4424132443151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4424132443051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5254313645 + ... + 5254314486.

It is an arithmetic number, because the mean of its divisors is an integer number (1108660267926).

Almost surely, 24424132443151 is an apocalyptic number.

4424132443151 is a deficient number, since it is larger than the sum of its proper divisors (10508628553).

4424132443151 is a wasteful number, since it uses less digits than its factorization.

4424132443151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10508628552.

The product of its digits is 184320, while the sum is 38.

Adding to 4424132443151 its reverse (1513442314244), we get a palindrome (5937574757395).

The spelling of 4424132443151 in words is "four trillion, four hundred twenty-four billion, one hundred thirty-two million, four hundred forty-three thousand, one hundred fifty-one".

Divisors: 1 421 10508628131 4424132443151