Base | Representation |
---|---|
bin | 100000001100001011110… |
… | …0101111000101000010011 |
3 | 120122221122221122022111002 |
4 | 1000120113211320220103 |
5 | 1034441241300402011 |
6 | 13224242140012215 |
7 | 634432046360354 |
oct | 100302745705023 |
9 | 16587587568432 |
10 | 4424212122131 |
11 | 145633044975a |
12 | 5b553783106b |
13 | 261280672b59 |
14 | 1141c0d97d2b |
15 | 7a13d2e5c3b |
hex | 40617978a13 |
4424212122131 has 2 divisors, whose sum is σ = 4424212122132. Its totient is φ = 4424212122130.
The previous prime is 4424212122119. The next prime is 4424212122149. The reversal of 4424212122131 is 1312212124244.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4424212122131 - 26 = 4424212122067 is a prime.
It is a super-2 number, since 2×44242121221312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4424212122094 and 4424212122103.
It is not a weakly prime, because it can be changed into another prime (4424212124131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2212106061065 + 2212106061066.
It is an arithmetic number, because the mean of its divisors is an integer number (2212106061066).
Almost surely, 24424212122131 is an apocalyptic number.
4424212122131 is a deficient number, since it is larger than the sum of its proper divisors (1).
4424212122131 is an equidigital number, since it uses as much as digits as its factorization.
4424212122131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6144, while the sum is 29.
Adding to 4424212122131 its reverse (1312212124244), we get a palindrome (5736424246375).
The spelling of 4424212122131 in words is "four trillion, four hundred twenty-four billion, two hundred twelve million, one hundred twenty-two thousand, one hundred thirty-one".
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