Base | Representation |
---|---|
bin | 100000001111011001000… |
… | …1110011001110001011001 |
3 | 120200121110002001000002012 |
4 | 1000132302032121301121 |
5 | 1040044343424332301 |
6 | 13231341521115305 |
7 | 635064552316115 |
oct | 100366216316131 |
9 | 16617402030065 |
10 | 4431101402201 |
11 | 145924624a851 |
12 | 5b693aa88b35 |
13 | 261b0aa50b36 |
14 | 114675d32745 |
15 | 7a3e303debb |
hex | 407b2399c59 |
4431101402201 has 2 divisors, whose sum is σ = 4431101402202. Its totient is φ = 4431101402200.
The previous prime is 4431101402191. The next prime is 4431101402213. The reversal of 4431101402201 is 1022041011344.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2967957146176 + 1463144256025 = 1722776^2 + 1209605^2 .
It is a cyclic number.
It is not a de Polignac number, because 4431101402201 - 26 = 4431101402137 is a prime.
It is not a weakly prime, because it can be changed into another prime (4431101402251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215550701100 + 2215550701101.
It is an arithmetic number, because the mean of its divisors is an integer number (2215550701101).
Almost surely, 24431101402201 is an apocalyptic number.
It is an amenable number.
4431101402201 is a deficient number, since it is larger than the sum of its proper divisors (1).
4431101402201 is an equidigital number, since it uses as much as digits as its factorization.
4431101402201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 4431101402201 its reverse (1022041011344), we get a palindrome (5453142413545).
The spelling of 4431101402201 in words is "four trillion, four hundred thirty-one billion, one hundred one million, four hundred two thousand, two hundred one".
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