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44311351055 = 58862270211
BaseRepresentation
bin101001010001001010…
…011000111100001111
311020101010121212022012
4221101022120330033
51211222201213210
632204550011435
73126035161256
oct512112307417
9136333555265
1044311351055
1117879669994
128707946b7b
13424234756a
14220500b79d
15124525e305
hexa51298f0f

44311351055 has 4 divisors (see below), whose sum is σ = 53173621272. Its totient is φ = 35449080840.

The previous prime is 44311351001. The next prime is 44311351079. The reversal of 44311351055 is 55015311344.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 44311351055 - 226 = 44244242191 is a prime.

It is a super-2 number, since 2×443113510552 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4431135101 + ... + 4431135110.

It is an arithmetic number, because the mean of its divisors is an integer number (13293405318).

Almost surely, 244311351055 is an apocalyptic number.

44311351055 is a deficient number, since it is larger than the sum of its proper divisors (8862270217).

44311351055 is an equidigital number, since it uses as much as digits as its factorization.

44311351055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8862270216.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 44311351055 its reverse (55015311344), we get a palindrome (99326662399).

The spelling of 44311351055 in words is "forty-four billion, three hundred eleven million, three hundred fifty-one thousand, fifty-five".

Divisors: 1 5 8862270211 44311351055