Base | Representation |
---|---|
bin | 1100111001011000001… |
… | …10000101110000100001 |
3 | 1120100202220010202012222 |
4 | 12130230012011300201 |
5 | 24230003041103231 |
6 | 535322302000425 |
7 | 44004650653352 |
oct | 6345406056041 |
9 | 1510686122188 |
10 | 443121425441 |
11 | 160a21546592 |
12 | 71a68576115 |
13 | 32a2b2aaab6 |
14 | 17639143d29 |
15 | b7d745c27b |
hex | 672c185c21 |
443121425441 has 2 divisors, whose sum is σ = 443121425442. Its totient is φ = 443121425440.
The previous prime is 443121425317. The next prime is 443121425471. The reversal of 443121425441 is 144524121344.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 441513736225 + 1607689216 = 664465^2 + 40096^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-443121425441 is a prime.
It is not a weakly prime, because it can be changed into another prime (443121425471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221560712720 + 221560712721.
It is an arithmetic number, because the mean of its divisors is an integer number (221560712721).
Almost surely, 2443121425441 is an apocalyptic number.
It is an amenable number.
443121425441 is a deficient number, since it is larger than the sum of its proper divisors (1).
443121425441 is an equidigital number, since it uses as much as digits as its factorization.
443121425441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 61440, while the sum is 35.
Adding to 443121425441 its reverse (144524121344), we get a palindrome (587645546785).
The spelling of 443121425441 in words is "four hundred forty-three billion, one hundred twenty-one million, four hundred twenty-five thousand, four hundred forty-one".
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