Base | Representation |
---|---|
bin | 10100001001101001110100… |
… | …00010011110101000000011 |
3 | 12210220012102000101210212001 |
4 | 22010310322002132220003 |
5 | 21302002241214233331 |
6 | 234124415444244431 |
7 | 12222306263360353 |
oct | 1204647202365003 |
9 | 183805360353761 |
10 | 44312151321091 |
11 | 13134750229365 |
12 | 4b77ba99a0717 |
13 | 1b958057c8904 |
14 | ad2a106c8b63 |
15 | 51c9da047561 |
hex | 284d3a09ea03 |
44312151321091 has 2 divisors, whose sum is σ = 44312151321092. Its totient is φ = 44312151321090.
The previous prime is 44312151321029. The next prime is 44312151321133. The reversal of 44312151321091 is 19012315121344.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 44312151321091 - 213 = 44312151312899 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 44312151321091.
It is not a weakly prime, because it can be changed into another prime (44312154321091) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22156075660545 + 22156075660546.
It is an arithmetic number, because the mean of its divisors is an integer number (22156075660546).
Almost surely, 244312151321091 is an apocalyptic number.
44312151321091 is a deficient number, since it is larger than the sum of its proper divisors (1).
44312151321091 is an equidigital number, since it uses as much as digits as its factorization.
44312151321091 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 37.
The spelling of 44312151321091 in words is "forty-four trillion, three hundred twelve billion, one hundred fifty-one million, three hundred twenty-one thousand, ninety-one".
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