Base | Representation |
---|---|
bin | 100000001111011100111… |
… | …1010100010100011101010 |
3 | 120200121210001210102200012 |
4 | 1000132321322202203222 |
5 | 1040100124441204114 |
6 | 13231402410211522 |
7 | 635101010020025 |
oct | 100367172424352 |
9 | 16617701712605 |
10 | 4431230413034 |
11 | 1459302056577 |
12 | 5b6976123ba2 |
13 | 261b2b6b12c9 |
14 | 1146891161bc |
15 | 7a3ee52463e |
hex | 407b9ea28ea |
4431230413034 has 8 divisors (see below), whose sum is σ = 6647171618340. Its totient is φ = 2215506540256.
The previous prime is 4431230413031. The next prime is 4431230413037. The reversal of 4431230413034 is 4303140321344.
It is an interprime number because it is at equal distance from previous prime (4431230413031) and next prime (4431230413037).
It can be written as a sum of positive squares in 2 ways, for example, as 4178970328009 + 252260085025 = 2044253^2 + 502255^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not an unprimeable number, because it can be changed into a prime (4431230413031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54282149 + ... + 54363720.
Almost surely, 24431230413034 is an apocalyptic number.
4431230413034 is a deficient number, since it is larger than the sum of its proper divisors (2215941205306).
4431230413034 is a wasteful number, since it uses less digits than its factorization.
4431230413034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 108666264.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 4431230413034 its reverse (4303140321344), we get a palindrome (8734370734378).
The spelling of 4431230413034 in words is "four trillion, four hundred thirty-one billion, two hundred thirty million, four hundred thirteen thousand, thirty-four".
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