Base | Representation |
---|---|
bin | 110010011000001101000011… |
… | …0000000010010011110001000 |
3 | 2011002222221002111222012121102 |
4 | 1210300122012000102132020 |
5 | 431040230201212120404 |
6 | 4210243355332200532 |
7 | 162224113222021265 |
oct | 14460320600223610 |
9 | 2132887074865542 |
10 | 443131204020104 |
11 | 119216985298706 |
12 | 41849967769148 |
13 | 16035129abb162 |
14 | 7b5d943d8026c |
15 | 3636cd5e8471e |
hex | 1930686012788 |
443131204020104 has 8 divisors (see below), whose sum is σ = 830871007537710. Its totient is φ = 221565602010048.
The previous prime is 443131204020079. The next prime is 443131204020163. The reversal of 443131204020104 is 401020402131344.
It can be written as a sum of positive squares in only one way, i.e., 400568601924100 + 42562602096004 = 20014210^2 + 6524002^2 .
It is a tau number, because it is divible by the number of its divisors (8).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27695700251249 + ... + 27695700251264.
Almost surely, 2443131204020104 is an apocalyptic number.
It is an amenable number.
443131204020104 is a deficient number, since it is larger than the sum of its proper divisors (387739803517606).
443131204020104 is a wasteful number, since it uses less digits than its factorization.
443131204020104 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55391400502519 (or 55391400502515 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 443131204020104 its reverse (401020402131344), we get a palindrome (844151606151448).
The spelling of 443131204020104 in words is "four hundred forty-three trillion, one hundred thirty-one billion, two hundred four million, twenty thousand, one hundred four".
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