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443131421104023 = 3147710473701341
BaseRepresentation
bin110010011000001101001001…
…0111100011001011110010111
32011002222221122122110012202120
41210300122102330121132113
5431040231122300312043
64210243433045111023
7162224121466141101
oct14460322274313627
92132887578405676
10443131421104023
11119216a8688a003
1241849a083b8473
1316035162a77492
147b5d964b2c571
153636cea065983
hex1930692f19797

443131421104023 has 4 divisors (see below), whose sum is σ = 590841894805368. Its totient is φ = 295420947402680.

The previous prime is 443131421103869. The next prime is 443131421104027. The reversal of 443131421104023 is 320401124131344.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 443131421104023 - 220 = 443131420055447 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (443131421104027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73855236850668 + ... + 73855236850673.

It is an arithmetic number, because the mean of its divisors is an integer number (147710473701342).

Almost surely, 2443131421104023 is an apocalyptic number.

443131421104023 is a deficient number, since it is larger than the sum of its proper divisors (147710473701345).

443131421104023 is a wasteful number, since it uses less digits than its factorization.

443131421104023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 147710473701344.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 443131421104023 its reverse (320401124131344), we get a palindrome (763532545235367).

The spelling of 443131421104023 in words is "four hundred forty-three trillion, one hundred thirty-one billion, four hundred twenty-one million, one hundred four thousand, twenty-three".

Divisors: 1 3 147710473701341 443131421104023