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443132424397913 is a prime number
BaseRepresentation
bin110010011000001101100111…
…0101111101010010001011001
32011010000001020120022211020112
41210300123032233222101121
5431040240201121213123
64210244120405134105
7162224155401041135
oct14460331657522131
92133001216284215
10443132424397913
11119217451152608
124184a0483ba335
13160352928989c3
147b5da1c0963c5
153636d58197d78
hex19306cebea459

443132424397913 has 2 divisors, whose sum is σ = 443132424397914. Its totient is φ = 443132424397912.

The previous prime is 443132424397847. The next prime is 443132424397921. The reversal of 443132424397913 is 319793424231344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 255941539337929 + 187190885059984 = 15998173^2 + 13681772^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-443132424397913 is a prime.

It is not a weakly prime, because it can be changed into another prime (443132424397933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221566212198956 + 221566212198957.

It is an arithmetic number, because the mean of its divisors is an integer number (221566212198957).

Almost surely, 2443132424397913 is an apocalyptic number.

It is an amenable number.

443132424397913 is a deficient number, since it is larger than the sum of its proper divisors (1).

443132424397913 is an equidigital number, since it uses as much as digits as its factorization.

443132424397913 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 47029248, while the sum is 59.

The spelling of 443132424397913 in words is "four hundred forty-three trillion, one hundred thirty-two billion, four hundred twenty-four million, three hundred ninety-seven thousand, nine hundred thirteen".