Base | Representation |
---|---|
bin | 100000001111100001000… |
… | …0011001011001001111001 |
3 | 120200122010120121101122020 |
4 | 1000133002003023021321 |
5 | 1040100414411103301 |
6 | 13231424123345053 |
7 | 635104255053222 |
oct | 100370203131171 |
9 | 16618116541566 |
10 | 4431366894201 |
11 | 14593720a4925 |
12 | 5b69b3982189 |
13 | 261b50a58ab0 |
14 | 11469d2c2249 |
15 | 7a40b4d3436 |
hex | 407c20cb279 |
4431366894201 has 32 divisors (see below), whose sum is σ = 6521865880320. Its totient is φ = 2659520857344.
The previous prime is 4431366894191. The next prime is 4431366894233. The reversal of 4431366894201 is 1024986631344.
4431366894201 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4431366894201 - 25 = 4431366894169 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4431366894281) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6073566 + ... + 6763943.
It is an arithmetic number, because the mean of its divisors is an integer number (203808308760).
Almost surely, 24431366894201 is an apocalyptic number.
It is an amenable number.
4431366894201 is a deficient number, since it is larger than the sum of its proper divisors (2090498986119).
4431366894201 is a wasteful number, since it uses less digits than its factorization.
4431366894201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12837745.
The product of its (nonzero) digits is 2985984, while the sum is 51.
It can be divided in two parts, 443136 and 6894201, that added together give a palindrome (7337337).
The spelling of 4431366894201 in words is "four trillion, four hundred thirty-one billion, three hundred sixty-six million, eight hundred ninety-four thousand, two hundred one".
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