4431423312241 has 4 divisors (see below), whose sum is σ = 4506532182000. Its totient is φ = 4356314442484.

The previous prime is 4431423312229. The next prime is 4431423312247. The reversal of 4431423312241 is 1422133241344.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4431423312241 - 2¹⁷ = 4431423181169 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4431423312197 and 4431423312206.

It is not an unprimeable number, because it can be changed into a prime (4431423312247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37554434791 + ... + 37554434908.

It is an arithmetic number, because the mean of its divisors is an integer number (1126633045500).

Almost surely, 2^{4431423312241} is an apocalyptic number.

It is an amenable number.

4431423312241 is a deficient number, since it is larger than the sum of its proper divisors (75108869759).

4431423312241 is an equidigital number, since it uses as much as digits as its factorization.

4431423312241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75108869758.

The product of its digits is 55296, while the sum is 34.

Adding to 4431423312241 its reverse (1422133241344), we get a palindrome (5853556553585).

The spelling of 4431423312241 in words is "four trillion, four hundred thirty-one billion, four hundred twenty-three million, three hundred twelve thousand, two hundred forty-one".