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4431423312247 is a prime number
BaseRepresentation
bin100000001111100010101…
…1010011001000101110111
3120200122021111202201122111
41000133011122121011313
51040101023331442442
613231433500511451
7635105541441301
oct100370532310567
916618244681574
104431423312247
1114593a0a29608
125b6a0a84b587
13261b5c650559
141146a69aa971
157a411429b17
hex407c5699177

4431423312247 has 2 divisors, whose sum is σ = 4431423312248. Its totient is φ = 4431423312246.

The previous prime is 4431423312229. The next prime is 4431423312287. The reversal of 4431423312247 is 7422133241344.

It is an a-pointer prime, because the next prime (4431423312287) can be obtained adding 4431423312247 to its sum of digits (40).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4431423312247 - 219 = 4431422787959 is a prime.

It is a super-3 number, since 3×44314233122473 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4431423312287) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215711656123 + 2215711656124.

It is an arithmetic number, because the mean of its divisors is an integer number (2215711656124).

Almost surely, 24431423312247 is an apocalyptic number.

4431423312247 is a deficient number, since it is larger than the sum of its proper divisors (1).

4431423312247 is an equidigital number, since it uses as much as digits as its factorization.

4431423312247 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 387072, while the sum is 40.

The spelling of 4431423312247 in words is "four trillion, four hundred thirty-one billion, four hundred twenty-three million, three hundred twelve thousand, two hundred forty-seven".