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44314400041 = 157312817011
BaseRepresentation
bin101001010001010110…
…000001010100101001
311020101100100202201121
4221101112001110221
51211223441300131
632205135215241
73126103120402
oct512126012451
9136340322647
1044314400041
111788036170a
128708977521
134242b742b2
1422055a29a9
151245662911
hexa51581529

44314400041 has 4 divisors (see below), whose sum is σ = 44317232784. Its totient is φ = 44311567300.

The previous prime is 44314400029. The next prime is 44314400051. The reversal of 44314400041 is 14000441344.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 44314400041 - 221 = 44312302889 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 44314399979 and 44314400015.

It is not an unprimeable number, because it can be changed into a prime (44314400051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1392775 + ... + 1424236.

It is an arithmetic number, because the mean of its divisors is an integer number (11079308196).

Almost surely, 244314400041 is an apocalyptic number.

It is an amenable number.

44314400041 is a deficient number, since it is larger than the sum of its proper divisors (2832743).

44314400041 is a wasteful number, since it uses less digits than its factorization.

44314400041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2832742.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 44314400041 its reverse (14000441344), we get a palindrome (58314841385).

The spelling of 44314400041 in words is "forty-four billion, three hundred fourteen million, four hundred thousand, forty-one".

Divisors: 1 15731 2817011 44314400041