Base | Representation |
---|---|
bin | 10100001001111000110101… |
… | …11110111001011010011011 |
3 | 12210220222020100110111120202 |
4 | 22010330122332321122123 |
5 | 21302120302334120011 |
6 | 234132232245012415 |
7 | 12223013242042166 |
oct | 1204743276713233 |
9 | 183828210414522 |
10 | 44320220223131 |
11 | 13138110987946 |
12 | 4b796800b410b |
13 | 1b964c03b4868 |
14 | ad31781aaadd |
15 | 51cd0d60323b |
hex | 284f1afb969b |
44320220223131 has 2 divisors, whose sum is σ = 44320220223132. Its totient is φ = 44320220223130.
The previous prime is 44320220223109. The next prime is 44320220223143. The reversal of 44320220223131 is 13132202202344.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 44320220223131 - 238 = 44045342316187 is a prime.
It is a super-2 number, since 2×443202202231312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 44320220223094 and 44320220223103.
It is not a weakly prime, because it can be changed into another prime (44320220223031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22160110111565 + 22160110111566.
It is an arithmetic number, because the mean of its divisors is an integer number (22160110111566).
Almost surely, 244320220223131 is an apocalyptic number.
44320220223131 is a deficient number, since it is larger than the sum of its proper divisors (1).
44320220223131 is an equidigital number, since it uses as much as digits as its factorization.
44320220223131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 44320220223131 its reverse (13132202202344), we get a palindrome (57452422425475).
The spelling of 44320220223131 in words is "forty-four trillion, three hundred twenty billion, two hundred twenty million, two hundred twenty-three thousand, one hundred thirty-one".
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