Base | Representation |
---|---|
bin | 100000001111111101001… |
… | …0110010000100001110010 |
3 | 120200201120101220022212211 |
4 | 1000133322112100201302 |
5 | 1040104333210433132 |
6 | 13232101544042334 |
7 | 635136544312621 |
oct | 100377226204162 |
9 | 16621511808784 |
10 | 4432311421042 |
11 | 145980727991a |
12 | 5b70181633aa |
13 | 261c7164260b |
14 | 11474c90d6b8 |
15 | 7a4643a8147 |
hex | 407fa590872 |
4432311421042 has 4 divisors (see below), whose sum is σ = 6648467131566. Its totient is φ = 2216155710520.
The previous prime is 4432311420973. The next prime is 4432311421061. The reversal of 4432311421042 is 2401241132344.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 3139881224841 + 1292430196201 = 1771971^2 + 1136851^2 .
It is a junction number, because it is equal to n+sod(n) for n = 4432311420995 and 4432311421013.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1108077855259 + ... + 1108077855262.
Almost surely, 24432311421042 is an apocalyptic number.
4432311421042 is a deficient number, since it is larger than the sum of its proper divisors (2216155710524).
4432311421042 is a wasteful number, since it uses less digits than its factorization.
4432311421042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2216155710523.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 4432311421042 its reverse (2401241132344), we get a palindrome (6833552553386).
The spelling of 4432311421042 in words is "four trillion, four hundred thirty-two billion, three hundred eleven million, four hundred twenty-one thousand, forty-two".
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