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443234314139 is a prime number
BaseRepresentation
bin1100111001100101101…
…00101110011110011011
31120101001202120002101212
412130302310232132123
524230220441023024
6535341413333335
744010521336051
oct6346264563633
91511052502355
10443234314139
11160a7a240531
1271a9a33724b
1332a487b4c46
141764a12c1d1
15b7e230aa0e
hex6732d2e79b

443234314139 has 2 divisors, whose sum is σ = 443234314140. Its totient is φ = 443234314138.

The previous prime is 443234314091. The next prime is 443234314183. The reversal of 443234314139 is 931413432344.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-443234314139 is a prime.

It is a super-2 number, since 2×4432343141392 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 443234314096 and 443234314105.

It is not a weakly prime, because it can be changed into another prime (443234314739) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221617157069 + 221617157070.

It is an arithmetic number, because the mean of its divisors is an integer number (221617157070).

Almost surely, 2443234314139 is an apocalyptic number.

443234314139 is a deficient number, since it is larger than the sum of its proper divisors (1).

443234314139 is an equidigital number, since it uses as much as digits as its factorization.

443234314139 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 373248, while the sum is 41.

The spelling of 443234314139 in words is "four hundred forty-three billion, two hundred thirty-four million, three hundred fourteen thousand, one hundred thirty-nine".