Base | Representation |
---|---|
bin | 10100001010010100100101… |
… | …01011000110011100010011 |
3 | 12210222101200021020012002111 |
4 | 22011022102223012130103 |
5 | 21302341302434421202 |
6 | 234143134141130151 |
7 | 12224051302213036 |
oct | 1205122253063423 |
9 | 183871607205074 |
10 | 44335113201427 |
11 | 13143463651974 |
12 | 4b80537859957 |
13 | 1b97a249cc059 |
14 | ad3b8c0d301d |
15 | 51d3d0d276d7 |
hex | 285292ac6713 |
44335113201427 has 2 divisors, whose sum is σ = 44335113201428. Its totient is φ = 44335113201426.
The previous prime is 44335113201391. The next prime is 44335113201451. The reversal of 44335113201427 is 72410231153344.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 44335113201427 - 223 = 44335104812819 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 44335113201427.
It is not a weakly prime, because it can be changed into another prime (44335110201427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22167556600713 + 22167556600714.
It is an arithmetic number, because the mean of its divisors is an integer number (22167556600714).
Almost surely, 244335113201427 is an apocalyptic number.
44335113201427 is a deficient number, since it is larger than the sum of its proper divisors (1).
44335113201427 is an equidigital number, since it uses as much as digits as its factorization.
44335113201427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 40.
The spelling of 44335113201427 in words is "forty-four trillion, three hundred thirty-five billion, one hundred thirteen million, two hundred one thousand, four hundred twenty-seven".
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