Base | Representation |
---|---|
bin | 101001010010111011… |
… | …111011011010010001 |
3 | 11020110012122000002111 |
4 | 221102323323122101 |
5 | 1211302311131023 |
6 | 32211531545321 |
7 | 3126546153223 |
oct | 512273733221 |
9 | 136405560074 |
10 | 44341114513 |
11 | 17894448693 |
12 | 87158bb241 |
13 | 4248568987 |
14 | 2208d58413 |
15 | 1247b8d00d |
hex | a52efb691 |
44341114513 has 2 divisors, whose sum is σ = 44341114514. Its totient is φ = 44341114512.
The previous prime is 44341114483. The next prime is 44341114583. The reversal of 44341114513 is 31541114344.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 44231137344 + 109977169 = 210312^2 + 10487^2 .
It is a cyclic number.
It is not a de Polignac number, because 44341114513 - 25 = 44341114481 is a prime.
It is a super-2 number, since 2×443411145132 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (44341114583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22170557256 + 22170557257.
It is an arithmetic number, because the mean of its divisors is an integer number (22170557257).
Almost surely, 244341114513 is an apocalyptic number.
It is an amenable number.
44341114513 is a deficient number, since it is larger than the sum of its proper divisors (1).
44341114513 is an equidigital number, since it uses as much as digits as its factorization.
44341114513 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11520, while the sum is 31.
Adding to 44341114513 its reverse (31541114344), we get a palindrome (75882228857).
The spelling of 44341114513 in words is "forty-four billion, three hundred forty-one million, one hundred fourteen thousand, five hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •