Base | Representation |
---|---|
bin | 101001010011000100… |
… | …010011111111001011 |
3 | 11020110100202122221011 |
4 | 221103010103333023 |
5 | 1211303341443311 |
6 | 32212051024351 |
7 | 3126603635653 |
oct | 512304237713 |
9 | 136410678834 |
10 | 44343312331 |
11 | 1789570996a |
12 | 871659b0b7 |
13 | 4248b58166 |
14 | 220936b363 |
15 | 1247e74321 |
hex | a53113fcb |
44343312331 has 2 divisors, whose sum is σ = 44343312332. Its totient is φ = 44343312330.
The previous prime is 44343312319. The next prime is 44343312347. The reversal of 44343312331 is 13321334344.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 44343312331 - 211 = 44343310283 is a prime.
It is a super-2 number, since 2×443433123312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 44343312293 and 44343312302.
It is not a weakly prime, because it can be changed into another prime (44343312371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22171656165 + 22171656166.
It is an arithmetic number, because the mean of its divisors is an integer number (22171656166).
Almost surely, 244343312331 is an apocalyptic number.
44343312331 is a deficient number, since it is larger than the sum of its proper divisors (1).
44343312331 is an equidigital number, since it uses as much as digits as its factorization.
44343312331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 31104, while the sum is 31.
Adding to 44343312331 its reverse (13321334344), we get a palindrome (57664646675).
The spelling of 44343312331 in words is "forty-four billion, three hundred forty-three million, three hundred twelve thousand, three hundred thirty-one".
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