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44380528462993 is a prime number
BaseRepresentation
bin10100001011101001001011…
…01000100100110010010001
312211010201220100001111221011
422011310211220210302101
521304112310241303433
6234220044443530521
712230246603445322
oct1205644550446221
9184121810044834
1044380528462993
1113160749357098
124b892b1229a41
131b9c0b19661a8
14ad605997a449
1551e68ce413cd
hex285d25a24c91

44380528462993 has 2 divisors, whose sum is σ = 44380528462994. Its totient is φ = 44380528462992.

The previous prime is 44380528462969. The next prime is 44380528462997. The reversal of 44380528462993 is 39926482508344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36963092553984 + 7417435909009 = 6079728^2 + 2723497^2 .

It is a cyclic number.

It is not a de Polignac number, because 44380528462993 - 229 = 44379991592081 is a prime.

It is not a weakly prime, because it can be changed into another prime (44380528462997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22190264231496 + 22190264231497.

It is an arithmetic number, because the mean of its divisors is an integer number (22190264231497).

Almost surely, 244380528462993 is an apocalyptic number.

It is an amenable number.

44380528462993 is a deficient number, since it is larger than the sum of its proper divisors (1).

44380528462993 is an equidigital number, since it uses as much as digits as its factorization.

44380528462993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 358318080, while the sum is 67.

The spelling of 44380528462993 in words is "forty-four trillion, three hundred eighty billion, five hundred twenty-eight million, four hundred sixty-two thousand, nine hundred ninety-three".