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4440333300113 is a prime number
BaseRepresentation
bin100000010011101100001…
…1111010011000110010001
3120201111021110111000020002
41000213120133103012101
51040222300311100423
613235505544455345
7635542412206304
oct100473037230621
916644243430202
104440333300113
111462153430347
125b869677a555
1326294c576219
14114cb0070b3b
157a783776228
hex409d87d3191

4440333300113 has 2 divisors, whose sum is σ = 4440333300114. Its totient is φ = 4440333300112.

The previous prime is 4440333300101. The next prime is 4440333300127. The reversal of 4440333300113 is 3110033330444.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4395324829009 + 45008471104 = 2096503^2 + 212152^2 .

It is a cyclic number.

It is not a de Polignac number, because 4440333300113 - 24 = 4440333300097 is a prime.

It is not a weakly prime, because it can be changed into another prime (4440333300413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2220166650056 + 2220166650057.

It is an arithmetic number, because the mean of its divisors is an integer number (2220166650057).

Almost surely, 24440333300113 is an apocalyptic number.

It is an amenable number.

4440333300113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4440333300113 is an equidigital number, since it uses as much as digits as its factorization.

4440333300113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 4440333300113 its reverse (3110033330444), we get a palindrome (7550366630557).

The spelling of 4440333300113 in words is "four trillion, four hundred forty billion, three hundred thirty-three million, three hundred thousand, one hundred thirteen".