4441242120137 has 2 divisors, whose sum is σ = 4441242120138. Its totient is φ = 4441242120136.

The previous prime is 4441242120097. The next prime is 4441242120173. The reversal of 4441242120137 is 7310212421444.

Together with next prime (4441242120173) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4288196073616 + 153046046521 = 2070796^2 + 391211^2 .

It is a cyclic number.

It is not a de Polignac number, because 4441242120137 - 2³⁰ = 4440168378313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4441242120097 and 4441242120106.

It is not a weakly prime, because it can be changed into another prime (4441242120437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2220621060068 + 2220621060069.

It is an arithmetic number, because the mean of its divisors is an integer number (2220621060069).

Almost surely, 2^{4441242120137} is an apocalyptic number.

It is an amenable number.

4441242120137 is a deficient number, since it is larger than the sum of its proper divisors (1).

4441242120137 is an equidigital number, since it uses as much as digits as its factorization.

4441242120137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43008, while the sum is 35.

The spelling of 4441242120137 in words is "four trillion, four hundred forty-one billion, two hundred forty-two million, one hundred twenty thousand, one hundred thirty-seven".