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4441242120481 is a prime number
BaseRepresentation
bin100000010100000111010…
…1010001011000100100001
3120201120121210120212101201
41000220032222023010201
51040231130440323411
613240140052001201
7635604056102335
oct100501652130441
916646553525351
104441242120481
11146257a437561
125b88ab000201
13262a6593a55a
14114d58a457c5
157a7d84463c1
hex40a0ea8b121

4441242120481 has 2 divisors, whose sum is σ = 4441242120482. Its totient is φ = 4441242120480.

The previous prime is 4441242120457. The next prime is 4441242120487. The reversal of 4441242120481 is 1840212421444.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3027568680081 + 1413673440400 = 1739991^2 + 1188980^2 .

It is a cyclic number.

It is not a de Polignac number, because 4441242120481 - 29 = 4441242119969 is a prime.

It is a super-2 number, since 2×44412421204812 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4441242120481.

It is not a weakly prime, because it can be changed into another prime (4441242120487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2220621060240 + 2220621060241.

It is an arithmetic number, because the mean of its divisors is an integer number (2220621060241).

Almost surely, 24441242120481 is an apocalyptic number.

It is an amenable number.

4441242120481 is a deficient number, since it is larger than the sum of its proper divisors (1).

4441242120481 is an equidigital number, since it uses as much as digits as its factorization.

4441242120481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 65536, while the sum is 37.

The spelling of 4441242120481 in words is "four trillion, four hundred forty-one billion, two hundred forty-two million, one hundred twenty thousand, four hundred eighty-one".