Base | Representation |
---|---|
bin | 110010011111111111010001… |
… | …0101000101010010110010011 |
3 | 2011020210012202120202120022111 |
4 | 1210333332202220222112103 |
5 | 431210242404043104134 |
6 | 4212423103233250151 |
7 | 162364321061131654 |
oct | 14477764250522623 |
9 | 2136705676676274 |
10 | 444201131222419 |
11 | 11959970730369a |
12 | 419a11a4103957 |
13 | 160b1caa3c328c |
14 | 7b9964148d52b |
15 | 3654a5672bc64 |
hex | 193ffa2a2a593 |
444201131222419 has 2 divisors, whose sum is σ = 444201131222420. Its totient is φ = 444201131222418.
The previous prime is 444201131222369. The next prime is 444201131222437. The reversal of 444201131222419 is 914222131102444.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 444201131222419 - 221 = 444201129125267 is a prime.
It is a super-2 number, since 2×4442011312224192 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (444201131222489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222100565611209 + 222100565611210.
It is an arithmetic number, because the mean of its divisors is an integer number (222100565611210).
Almost surely, 2444201131222419 is an apocalyptic number.
444201131222419 is a deficient number, since it is larger than the sum of its proper divisors (1).
444201131222419 is an equidigital number, since it uses as much as digits as its factorization.
444201131222419 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 40.
The spelling of 444201131222419 in words is "four hundred forty-four trillion, two hundred one billion, one hundred thirty-one million, two hundred twenty-two thousand, four hundred nineteen".
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