Base | Representation |
---|---|
bin | 1100111011011100010… |
… | …11110001010111000101 |
3 | 1120110122011111220002021 |
4 | 12131232023301113011 |
5 | 24234240413223023 |
6 | 540024311043141 |
7 | 44044303330351 |
oct | 6355613612705 |
9 | 1513564456067 |
10 | 444230211013 |
11 | 1614404115a6 |
12 | 721179704b1 |
13 | 32b76c16634 |
14 | 177024cc461 |
15 | b84e97b35d |
hex | 676e2f15c5 |
444230211013 has 4 divisors (see below), whose sum is σ = 444232988928. Its totient is φ = 444227433100.
The previous prime is 444230210959. The next prime is 444230211043. The reversal of 444230211013 is 310112032444.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-444230211013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (444230211043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1133413 + ... + 1474138.
It is an arithmetic number, because the mean of its divisors is an integer number (111058247232).
Almost surely, 2444230211013 is an apocalyptic number.
It is an amenable number.
444230211013 is a deficient number, since it is larger than the sum of its proper divisors (2777915).
444230211013 is a wasteful number, since it uses less digits than its factorization.
444230211013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2777914.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 444230211013 its reverse (310112032444), we get a palindrome (754342243457).
The spelling of 444230211013 in words is "four hundred forty-four billion, two hundred thirty million, two hundred eleven thousand, thirteen".
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