4444100450131 has 2 divisors, whose sum is σ = 4444100450132. Its totient is φ = 4444100450130.

The previous prime is 4444100450093. The next prime is 4444100450143. The reversal of 4444100450131 is 1310540014444.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4444100450131 - 2³¹ = 4441952966483 is a prime.

It is a super-3 number, since 3×4444100450131³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 4444100450093 and 4444100450102.

It is not a weakly prime, because it can be changed into another prime (4444100450171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2222050225065 + 2222050225066.

It is an arithmetic number, because the mean of its divisors is an integer number (2222050225066).

Almost surely, 2^{4444100450131} is an apocalyptic number.

4444100450131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4444100450131 is an equidigital number, since it uses as much as digits as its factorization.

4444100450131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15360, while the sum is 31.

Adding to 4444100450131 its reverse (1310540014444), we get a palindrome (5754640464575).

The spelling of 4444100450131 in words is "four trillion, four hundred forty-four billion, one hundred million, four hundred fifty thousand, one hundred thirty-one".